3x^2+4x+1=-2x-2

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Solution for 3x^2+4x+1=-2x-2 equation: 



3x^2+4x+1=-2x-2

We move all terms to the left:

3x^2+4x+1-(-2x-2)=0

We get rid of parentheses

3x^2+4x+2x+2+1=0

We add all the numbers together, and all the variables

3x^2+6x+3=0

a = 3; b = 6; c = +3;
Δ = b2-4ac
Δ = 62-4·3·3
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-6}{6}=-1$

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